What is the integral of 2/((3x+1)) ?

The integral of 2/((3x+1)) is 2/3 ln|3x+1|+C

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integral of 2/((3x+1))

integral

\frac{2}{( 3 x + 1 )}

\frac{2}{3} ln ∣ 3 x + 1 ∣ + C

Solution steps

\int \frac{2}{3 x + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{3 x + 1} d x

Apply u-substitution

: \int \frac{1}{3 u} d u

= 2 \cdot \int \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 2 \cdot \frac{1}{3} ln ∣ u ∣

Substitute back

u = 3 x + 1

= 2 \cdot \frac{1}{3} ln ∣ 3 x + 1 ∣

Simplify

2 \cdot \frac{1}{3} ln ∣ 3 x + 1 ∣ : \frac{2}{3} ln ∣ 3 x + 1 ∣

= \frac{2}{3} ln ∣ 3 x + 1 ∣

Add a constant to the solution

= \frac{2}{3} ln ∣ 3 x + 1 ∣ + C

\frac{( 2 x + 3 )}{( 2 x - 1 ) ^{2}}

x^{2} \cdot arctan (x)

\frac{1}{( x ^{2} ( x - 1 ) )}

\frac{lo g _{10} ( ( 1 + x ) ^{2} )}{x ^{2}}

\frac{1}{( x ln ( x ) )}

What is the integral of 2/((3x+1)) ?
The integral of 2/((3x+1)) is 2/3 ln|3x+1|+C