What is the integral of sin(8z)-5 ?

The integral of sin(8z)-5 is -1/8 cos(8z)-5z+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin(8z)-5

integral

sin (8 z) - 5

- \frac{1}{8} cos (8 z) - 5 z + C

Solution steps

\int sin (8 z) - 5 d z

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (8 z) d z - \int 5 d z

\int sin (8 z) d z = - \frac{1}{8} cos (8 z)

\int 5 d z = 5 z

= - \frac{1}{8} cos (8 z) - 5 z

Add a constant to the solution

= - \frac{1}{8} cos (8 z) - 5 z + C

\frac{- 4 x}{( x ^{4} - 2 x ^{2} + 1 )}

\frac{5}{x ^{3}}

x^{2} sec^{2} (x)

\frac{1}{( 3 x ^{2} + 2 x + 1 )}

\frac{sin ^{4} ( x )}{sin ( x )}

What is the integral of sin(8z)-5 ?
The integral of sin(8z)-5 is -1/8 cos(8z)-5z+C