What is the integral of sec^2(x)tan(x) ?

The integral of sec^2(x)tan(x) is (tan^2(x))/2+C

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integral of sec^2(x)tan(x)

integral

sec^{2} (x) tan (x)

\frac{tan ^{2} ( x )}{2} + C

Solution steps

\int sec^{2} (x) tan (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = tan (x)

= \frac{tan ^{2} ( x )}{2}

Add a constant to the solution

= \frac{tan ^{2} ( x )}{2} + C

\frac{300}{( 2 x + 1 )} + 12 x^{3} - 8 x

sin^{5} (\frac{x}{3}) cos (\frac{x}{3})

\frac{3 x ^{3}}{( 1 - x )}

\frac{1}{1} + x^{2} \frac{x ^{2}}{2}

\frac{- y}{( 1 + y ^{2} )}

What is the integral of sec^2(x)tan(x) ?
The integral of sec^2(x)tan(x) is (tan^2(x))/2+C