What is the f(x)=(((x-1))/((x+1)))^{1/2} ?

The f(x)=(((x-1))/((x+1)))^{1/2} is

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f(x)=(((x-1))/((x+1)))^{1/2}

f (x) = (\frac{( x - 1 )}{( x + 1 )})^{\frac{1}{2}}

Domain : x < - 1 or x \geq 1

Range : 0 \leq f (x) < 1 or f (x) > 1

X Intercepts : (1, 0)

Asymptotes : Vertical x = - 1, Horizontal y = 1

Extreme Points : Minimum (1, 0)

Interval Notation

Solution steps

Domain of

(\frac{x - 1}{x + 1})^{\frac{1}{2}} : x < - 1 or x \geq 1

Range of

(\frac{x - 1}{x + 1})^{\frac{1}{2}} : 0 \leq f (x) < 1 or f (x) > 1

Axis interception points of

(\frac{x - 1}{x + 1})^{\frac{1}{2}} :

X Intercepts

: (1, 0)

Asymptotes of

(\frac{x - 1}{x + 1})^{\frac{1}{2}} :

Vertical

: x = - 1,

Horizontal

: y = 1

Extreme Points of

(\frac{x - 1}{x + 1})^{\frac{1}{2}} :

Minimum

(1, 0)

sin^{2} (x) cos^{3} (x)

\frac{sin ( x )}{( 1 - sin ( x ) )}

\frac{1}{v ^{4}}

\frac{( x ^{2} - 1 )}{( x ^{2} - 4 x + 1 )}

\frac{( x ^{3} + 2 )}{( 4 - x ^{2} )}