What is the integral of t^2e^t ?

The integral of t^2e^t is t^2e^t-2(e^tt-e^t)+C

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integral of t^2e^t

integral

t^{2} e^{t}

t^{2} e^{t} - 2 (e^{t} t - e^{t}) + C

Solution steps

\int t^{2} e^{t} d t

Apply Integration By Parts

: t^{2} e^{t} - \int 2 t e^{t} d t

= t^{2} e^{t} - \int 2 t e^{t} d t

\int 2 t e^{t} d t = 2 (e^{t} t - e^{t})

= t^{2} e^{t} - 2 (e^{t} t - e^{t})

Add a constant to the solution

= t^{2} e^{t} - 2 (e^{t} t - e^{t}) + C

5 y^{2} (e^{x})^{2}

- 0.5 x^{2}

sin (x) + 2 cos (x)

sin^{3} (2 x)

\frac{x}{( 2 x + 1 ) ^{2}}