What is the integral of 1/(cos^2(y)) ?

The integral of 1/(cos^2(y)) is tan(y)+C

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integral of 1/(cos^2(y))

integral

\frac{1}{cos ^{2} ( y )}

tan (y) + C

Solution steps

\int \frac{1}{cos ^{2} ( y )} d y

Use the common integral:

\int \frac{1}{cos ^{2} ( y )} d y = tan (y)

= tan (y)

Add a constant to the solution

= tan (y) + C

\frac{x ^{2}}{x}

3 - 5 x^{2}

\frac{2 sin ( x )}{( 5 + 3 cos ( x ) )}

f (x) = 3 x + 1

v^{2}