What is the integral of 2e^{-x} ?

The integral of 2e^{-x} is -2e^{-x}+C

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integral of 2e^{-x}

integral

2 e^{- x}

- 2 e^{- x} + C

Solution steps

\int 2 e^{- x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{- x} d x

Apply u-substitution

: \int - e^{u} d u

= 2 \cdot \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 2 (- e^{u})

Substitute back

u = - x

= 2 (- e^{- x})

Simplify

= - 2 e^{- x}

Add a constant to the solution

= - 2 e^{- x} + C

\frac{1}{( 1 + x ^{2} ) ^{0.5}}

\frac{- 1}{y + 1}

x^{2} e^{2} x

\frac{3}{x ^{4}}

\frac{e ^{x}}{x ^{4}}