What is the integral of (10)/(x^3) ?

The integral of (10)/(x^3) is -5/(x^2)+C

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integral of (10)/(x^3)

integral

\frac{10}{x ^{3}}

- \frac{5}{x ^{2}} + C

Solution steps

\int \frac{10}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 10 (- \frac{1}{2 x ^{2}})

Simplify

10 (- \frac{1}{2 x ^{2}}) : - \frac{5}{x ^{2}}

= - \frac{5}{x ^{2}}

Add a constant to the solution

= - \frac{5}{x ^{2}} + C

3 x^{5} - 8 x^{4}

\frac{2 x ^{2}}{( x ^{2} + 1 )}

2 - x^{2}

\frac{( 6 x + 1 )}{( 2 x - 3 )}

\frac{9}{( 3 x - 4 ) ^{2}}