What is the integral of x^4e^x ?

The integral of x^4e^x is x^4e^x-4(x^3e^x-3(x^2e^x-2(e^xx-e^x)))+C

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integral of x^4e^x

integral

x^{4} e^{x}

x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x}))) + C

Solution steps

\int x^{4} e^{x} d x

Apply Integration By Parts

: x^{4} e^{x} - \int 4 x^{3} e^{x} d x

= x^{4} e^{x} - \int 4 x^{3} e^{x} d x

\int 4 x^{3} e^{x} d x = 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x})))

= x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x})))

Add a constant to the solution

= x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x}))) + C

(1 + x)^{\frac{1}{4}}

e^{(8 x)^{2}}

ln (1 - x)

\frac{( 2 x + 4 )}{( x ^{3} - 1 )}

(x^{2} + 5) \cdot 2^{x}

What is the integral of x^4e^x ?
The integral of x^4e^x is x^4e^x-4(x^3e^x-3(x^2e^x-2(e^xx-e^x)))+C