What is the integral of (e^{2x})/x ?

The integral of (e^{2x})/x is \Ei(2x)+C

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integral of (e^{2x})/x

integral

\frac{e ^{2 x}}{x}

Ei (2 x) + C

Solution steps

\int \frac{e ^{2 x}}{x} d x

Apply u-substitution

: \int \frac{e ^{u}}{u} d u

= \int \frac{e ^{u}}{u} d u

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= Ei (u)

Substitute back

u = 2 x

= Ei (2 x)

Add a constant to the solution

= Ei (2 x) + C

\frac{1}{( x + 1 ) ^{5}}

e^{1 + x}

\frac{1}{( x ( x + 1 ) ^{2} )}

f (x) = 2 x cos (x)

\frac{1}{( a ^{x} + 1 )}