What is the integral of (arctan(x))/(x^2) ?

The integral of (arctan(x))/(x^2) is -(arctan(x))/x+ln|x|-1/2 ln|x^2+1|+C

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integral of (arctan(x))/(x^2)

integral

\frac{arctan ( x )}{x ^{2}}

- \frac{arctan ( x )}{x} + ln ∣ x ∣ - \frac{1}{2} ln x^{2} + 1 + C

Solution steps

\int \frac{arctan ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{arctan ( x )}{x} - \int - \frac{1}{x ( x ^{2} + 1 )} d x

= - \frac{arctan ( x )}{x} - \int - \frac{1}{x ( x ^{2} + 1 )} d x

\int - \frac{1}{x ( x ^{2} + 1 )} d x = - ln ∣ x ∣ + \frac{1}{2} ln x^{2} + 1

= - \frac{arctan ( x )}{x} - (- ln ∣ x ∣ + \frac{1}{2} ln x^{2} + 1)

Simplify

= - \frac{arctan ( x )}{x} + ln ∣ x ∣ - \frac{1}{2} ln x^{2} + 1

Add a constant to the solution

= - \frac{arctan ( x )}{x} + ln ∣ x ∣ - \frac{1}{2} ln x^{2} + 1 + C

\frac{t ^{3}}{( t + 1 ) ^{2}}

\frac{1}{( x - 2 ) ^{3} ( x + 4 ) ^{4}}

x^{2} \cdot (\frac{1 - 2}{x})^{2}

(1 + x tan (x) - sin (x)) sec^{2} (x)

cos^{2} (x) - sin^{2} (x)

What is the integral of (arctan(x))/(x^2) ?
The integral of (arctan(x))/(x^2) is -(arctan(x))/x+ln|x|-1/2 ln|x^2+1|+C