What is the integral of ((1-1)/n)^{n-1} ?

The integral of ((1-1)/n)^{n-1} is C

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integral of ((1-1)/n)^{n-1}

integral

(\frac{1 - 1}{n})^{n - 1}

C

Solution steps

\int (\frac{1 - 1}{n})^{n - 1} d n

Simplify

= \int 0 d n

Integral of a constant:

\int a d x = a x

= 0 \cdot n

Simplify

= 0

Add a constant to the solution

= 0 + C

= C

x^{2} ln (x + 1)

x (1 + x^{2})^{15}

\frac{x}{x ^{2} + y ^{2}}

(x^{2} + 1)^{\frac{1}{2}}

\frac{1}{4 - x ^{2} - 4 x}