What is the solution for x^{''}+kx=0 ?

The solution for x^{''}+kx=0 is x=c_{1}cos(sqrt(k)t)+c_{2}sin(sqrt(k)t)

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x^{''}+kx=0

x^{^{''}} + k x = 0

x = c_{1} cos (k t) + c_{2} sin (k t)

Solution steps

x^{''} (t) + k x (t) = 0

Solve linear ODE:

x = c_{1} cos (k t) + c_{2} sin (k t)

x = c_{1} cos (k t) + c_{2} sin (k t)

y = \frac{4}{x}, y = 4 x, x = 4, x = 0

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\frac{d}{d x} (e^{x} + 3 e^{- x})

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\int \frac{( x + 6 )}{x + 7} d x

What is the solution for x^{''}+kx=0 ?
The solution for x^{''}+kx=0 is x=c_{1}cos(sqrt(k)t)+c_{2}sin(sqrt(k)t)