What is the integral of 1/((x+2)^2) ?

The integral of 1/((x+2)^2) is -1/(x+2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((x+2)^2)

integral

\frac{1}{( x + 2 ) ^{2}}

- \frac{1}{x + 2} + C

Solution steps

\int \frac{1}{( x + 2 ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = x + 2

= - \frac{1}{x + 2}

Add a constant to the solution

= - \frac{1}{x + 2} + C

x^{2} (a^{2} - x^{2})^{\frac{1}{2}}

\frac{( 2 x - 1 )}{( 2 x + 3 )}

\frac{cos ( 2 x )}{cos ( x )}

\frac{( x + 8 ) ^{2}}{x ^{2} + 7 x - 8}

\frac{( 1 - cos ( x ) )}{sin ^{2} ( x )}