What is the integral of (x^2)/((x^3+1)^{1/2)} ?

The integral of (x^2)/((x^3+1)^{1/2)} is 2/3 (x^3+1)^{1/2}+C

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integral of (x^2)/((x^3+1)^{1/2)}

integral

\frac{x ^{2}}{( x ^{3} + 1 ) ^{\frac{1}{2}}}

\frac{2}{3} (x^{3} + 1)^{\frac{1}{2}} + C

Solution steps

\int \frac{x ^{2}}{( x ^{3} + 1 ) ^{\frac{1}{2}}} d x

Apply u-substitution

: \int \frac{1}{3 u ^{\frac{1}{2}}} d u

= \int \frac{1}{3 u ^{\frac{1}{2}}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1}{u ^{\frac{1}{2}}} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= \frac{1}{3} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = x^{3} + 1

= \frac{1}{3} \cdot 2 (x^{3} + 1)^{\frac{1}{2}}

Simplify

\frac{1}{3} \cdot 2 (x^{3} + 1)^{\frac{1}{2}} : \frac{2}{3} (x^{3} + 1)^{\frac{1}{2}}

= \frac{2}{3} (x^{3} + 1)^{\frac{1}{2}}

Add a constant to the solution

= \frac{2}{3} (x^{3} + 1)^{\frac{1}{2}} + C

\frac{- 2}{e ^{x}}

\frac{1}{( x ( x ^{2} + x + 1 ) )}

5 (1 - x)^{4}

\frac{1}{( 1 - x ^{3} )}

y = 2 x^{3} - 5 x + 4

What is the integral of (x^2)/((x^3+1)^{1/2)} ?
The integral of (x^2)/((x^3+1)^{1/2)} is 2/3 (x^3+1)^{1/2}+C