What is the integral of (sqrt(x)+1)/((sqrt(x))) ?

The integral of (sqrt(x)+1)/((sqrt(x))) is x+2sqrt(x)+C

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integral of (sqrt(x)+1)/((sqrt(x)))

integral

\frac{x + 1}{( x )}

x + 2 x + C

Solution steps

\int \frac{x + 1}{x} d x

Expand

\frac{x + 1}{x} : 1 + \frac{1}{x}

= \int 1 + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x + \int \frac{1}{x} d x

\int 1 d x = x

\int \frac{1}{x} d x = 2 x

= x + 2 x

Add a constant to the solution

= x + 2 x + C

\frac{e}{( ( e ) ^{x} ) ^{2}}

\frac{( x - 2 )}{( x - 1 )}

z (1 + i)

r^{- 1}

ln ((\frac{1}{x}) - 1)

What is the integral of (sqrt(x)+1)/((sqrt(x))) ?
The integral of (sqrt(x)+1)/((sqrt(x))) is x+2sqrt(x)+C