What is the integral of 1/((sqrt(1+x^2))) ?

The integral of 1/((sqrt(1+x^2))) is ln|sqrt(x^2+1)+x|+C

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integral of 1/((sqrt(1+x^2)))

integral

\frac{1}{( 1 + x ^{2} )}

ln x^{2} + 1 + x + C

Solution steps

\int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = ln x^{2} + 1 + x

= ln x^{2} + 1 + x

Add a constant to the solution

= ln x^{2} + 1 + x + C

\frac{x ( 1 + 3 x ^{2} ) ^{5}}{2}

\frac{2}{t ^{3}}

\frac{x}{sin ^{2} ( x ^{2} )}

\frac{x}{16}

\frac{cos ^{2} ( 2 x )}{sin ( 2 x )}

What is the integral of 1/((sqrt(1+x^2))) ?
The integral of 1/((sqrt(1+x^2))) is ln|sqrt(x^2+1)+x|+C