What is the integral of ((x^2-x+1))/(x^3) ?

The integral of ((x^2-x+1))/(x^3) is ln|x|+1/x-1/(2x^2)+C

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integral of ((x^2-x+1))/(x^3)

integral

\frac{( x ^{2} - x + 1 )}{x ^{3}}

ln ∣ x ∣ + \frac{1}{x} - \frac{1}{2 x ^{2}} + C

Solution steps

\int \frac{x ^{2} - x + 1}{x ^{3}} d x

Expand

\frac{x ^{2} - x + 1}{x ^{3}} : \frac{1}{x} - \frac{1}{x ^{2}} + \frac{1}{x ^{3}}

= \int \frac{1}{x} - \frac{1}{x ^{2}} + \frac{1}{x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x - \int \frac{1}{x ^{2}} d x + \int \frac{1}{x ^{3}} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}}

= ln ∣ x ∣ - (- \frac{1}{x}) - \frac{1}{2 x ^{2}}

Simplify

= ln ∣ x ∣ + \frac{1}{x} - \frac{1}{2 x ^{2}}

Add a constant to the solution

= ln ∣ x ∣ + \frac{1}{x} - \frac{1}{2 x ^{2}} + C

\frac{( e ^{x} )}{x ^{- 2}}

\frac{1}{( 5 + 2 x + x ^{2} ) ^{\frac{3}{2}}}

\frac{1}{( 1 + 2 x ) ^{2}}

cos (x) - 1

\frac{( x - 2 )}{( 2 x ^{2} - 8 x - 1 )}

What is the integral of ((x^2-x+1))/(x^3) ?
The integral of ((x^2-x+1))/(x^3) is ln|x|+1/x-1/(2x^2)+C