What is the integral of (log_{10}(1))/x ?

The integral of (log_{10}(1))/x is C

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integral of (log_{10}(1))/x

integral

\frac{lo g _{10} ( 1 )}{x}

C

Solution steps

\int \frac{lo g _{10} ( 1 )}{x} d x

\frac{lo g _{10} ( 1 )}{x} = 0

= \int 0 d x

Integral of a constant:

\int a d x = a x

= 0 \cdot x

Simplify

= 0

Add a constant to the solution

= 0 + C

= C

\frac{x}{( x ^{2} + 1 ) ^{3}}

\frac{( x + 8 )}{( x + 7 )}

\frac{x ^{2} + 1}{( x + 1 ) 2}

\frac{81 x ^{2}}{9 x - 2}

4 cos^{2} (x) - 2 sin^{2} (x)