What is the integral of 2+3cos(0.5x) ?

The integral of 2+3cos(0.5x) is 2x+6sin(0.5x)+C

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integral of 2+3cos(0.5x)

integral

2 + 3 cos (0.5 x)

2 x + 6 sin (0.5 x) + C

Solution steps

\int 2 + 3 cos (0.5 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x + \int 3 cos (0.5 x) d x

\int 2 d x = 2 x

\int 3 cos (0.5 x) d x = 6 sin (0.5 x)

= 2 x + 6 sin (0.5 x)

Add a constant to the solution

= 2 x + 6 sin (0.5 x) + C

v = \frac{1}{3 t + 2}

(3 x + 9)^{4}

\frac{( x + 1 )}{( x ^{2} + x + 1 )}

ln (\frac{e ^{x}}{x ^{2}})

(x^{2} - a^{2})^{\frac{1}{2}}

What is the integral of 2+3cos(0.5x) ?
The integral of 2+3cos(0.5x) is 2x+6sin(0.5x)+C