What is the integral of (x+1)sin(x^2+2x+3) ?

The integral of (x+1)sin(x^2+2x+3) is -1/2 cos(x^2+2x+3)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x+1)sin(x^2+2x+3)

integral

(x + 1) sin (x^{2} + 2 x + 3)

- \frac{1}{2} cos (x^{2} + 2 x + 3) + C

Solution steps

\int (x + 1) sin (x^{2} + 2 x + 3) d x

Apply u-substitution

: \int u sin (u^{2} + 2) d u

= \int u sin (u^{2} + 2) d u

Apply u-substitution

: \int \frac{sin ( v )}{2} d v

= \int \frac{sin ( v )}{2} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (v) d v

Use the common integral:

\int sin (v) d v = - cos (v)

= \frac{1}{2} (- cos (v))

Substitute back

= \frac{1}{2} (- cos ((x + 1)^{2} + 2))

Simplify

\frac{1}{2} (- cos ((x + 1)^{2} + 2)) : - \frac{1}{2} cos (x^{2} + 2 x + 3)

= - \frac{1}{2} cos (x^{2} + 2 x + 3)

Add a constant to the solution

= - \frac{1}{2} cos (x^{2} + 2 x + 3) + C

x \cdot (x^{2} + 1)^{\frac{1}{2}}

ln (a^{2} - x^{2})

(x^{3} - 1)^{5}

\frac{x ^{2}}{x + 4}

y^{2} \cdot 2 (x^{2} - y^{2})^{\frac{1}{2}}

What is the integral of (x+1)sin(x^2+2x+3) ?
The integral of (x+1)sin(x^2+2x+3) is -1/2 cos(x^2+2x+3)+C