What is the integral of (2x+3)^4 ?

The integral of (2x+3)^4 is 1/10 (2x+3)^5+C

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integral of (2x+3)^4

integral

(2 x + 3)^{4}

\frac{1}{10} (2 x + 3)^{5} + C

Solution steps

\int (2 x + 3)^{4} d x

Apply u-substitution

: \int \frac{u ^{4}}{2} d u

= \int \frac{u ^{4}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{1}{2} \cdot \frac{u ^{5}}{5}

Substitute back

u = 2 x + 3

= \frac{1}{2} \cdot \frac{( 2 x + 3 ) ^{5}}{5}

Simplify

\frac{1}{2} \cdot \frac{( 2 x + 3 ) ^{5}}{5} : \frac{1}{10} (2 x + 3)^{5}

= \frac{1}{10} (2 x + 3)^{5}

Add a constant to the solution

= \frac{1}{10} (2 x + 3)^{5} + C

e \cdot x^{2}

e^{2 x^{2}}

x^{2} + 6 x

(3 x + 1)^{3} ln (3 x + 1)

\frac{( 4 x + 16 )}{( x ^{2} + 6 x + 13 )}