What is the integral of 1/((2x^3)) ?

The integral of 1/((2x^3)) is -1/(4x^2)+C

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integral of 1/((2x^3))

integral

\frac{1}{( 2 x ^{3} )}

- \frac{1}{4 x ^{2}} + C

Solution steps

\int \frac{1}{2 x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= \frac{1}{2} (- \frac{1}{2 x ^{2}})

Simplify

\frac{1}{2} (- \frac{1}{2 x ^{2}}) : - \frac{1}{4 x ^{2}}

= - \frac{1}{4 x ^{2}}

Add a constant to the solution

= - \frac{1}{4 x ^{2}} + C

sec^{2} (2 x - 1)

y = [3 x + 2] [2 x - 5]

\frac{1}{( k + e ^{- t} )}

e^{\frac{y ^{2}}{2}}

x (x^{2})