What is the integral of (1-y)^4 ?

The integral of (1-y)^4 is -((1-y)^5)/5+C

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integral of (1-y)^4

integral

(1 - y)^{4}

- \frac{( 1 - y ) ^{5}}{5} + C

Solution steps

\int (1 - y)^{4} d y

Apply u-substitution

: \int - u^{4} d u

= \int - u^{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= - \frac{u ^{5}}{5}

Substitute back

u = 1 - y

= - \frac{( 1 - y ) ^{5}}{5}

Add a constant to the solution

= - \frac{( 1 - y ) ^{5}}{5} + C

(2 x + 1)^{- 3}

\frac{1}{( 9 x ^{2} + 4 )}

y = \frac{1}{x ^{\frac{1}{2}}}

(\frac{1}{2})^{x}

\frac{e ^{2} x - 1}{e ^{2} x + 1}