What is the derivative of 2(3-8x^3) ?

The derivative of 2(3-8x^3) is -48(3-8x)^2

What is the first derivative of 2(3-8x^3) ?

The first derivative of 2(3-8x^3) is -48(3-8x)^2

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\frac{d}{d x} (2 (3 - 8 x)^{3})

- 48 (3 - 8 x)^{2}

Solution steps

\frac{d}{d x} (2 (3 - 8 x)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((3 - 8 x)^{3})

Apply the chain rule:

3 (3 - 8 x)^{2} \frac{d}{d x} (3 - 8 x)

= 3 (3 - 8 x)^{2} \frac{d}{d x} (3 - 8 x)

\frac{d}{d x} (3 - 8 x) = - 8

= 2 \cdot 3 (3 - 8 x)^{2} (- 8)

Simplify

= - 48 (3 - 8 x)^{2}

\frac{d}{d y} (x^{2} y z)

\frac{d}{d x} ((4 x^{2} - 8 x + 8) e^{x})

\int \frac{1}{( x - 8 ) ( x ^{2} + 25 )} d x

\int 2 x (x^{2} + 1)^{9} d x

\frac{d}{d x} (- (x + 1) sin (\frac{x ^{2}}{2}))

What is the derivative of 2(3-8x^3) ?
The derivative of 2(3-8x^3) is -48(3-8x)^2
What is the first derivative of 2(3-8x^3) ?
The first derivative of 2(3-8x^3) is -48(3-8x)^2