What is the integral of 1/((sqrt(x))) ?

The integral of 1/((sqrt(x))) is 2sqrt(x)+C

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integral of 1/((sqrt(x)))

integral

\frac{1}{( x )}

2 x + C

Solution steps

\int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Apply radical rule:

a^{\frac{1}{n}} = n a

= 2 x

Add a constant to the solution

= 2 x + C

\frac{x ^{2}}{( 4 + x ^{6} )}

\frac{1}{x} + \frac{1}{x ^{3}}

\frac{( 3 x - 13 )}{( x ^{2} - 12 + 45 ) ^{2}}

4 x^{3} + 5 x^{4} + 3

\frac{( x + 5 )}{( - 3 x )}

What is the integral of 1/((sqrt(x))) ?
The integral of 1/((sqrt(x))) is 2sqrt(x)+C