What is the integral of 2/((1+x^2)) ?

The integral of 2/((1+x^2)) is 2arctan(x)+C

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integral of 2/((1+x^2))

integral

\frac{2}{( 1 + x ^{2} )}

2 arctan (x) + C

Solution steps

\int \frac{2}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 2 arctan (x)

Add a constant to the solution

= 2 arctan (x) + C

\frac{ln ( t )}{( t + 1 ) ^{2}}

\frac{x ^{2}}{( x ^{2} - 2 x + 2 ) ^{2}}

(u^{2}) (1 + u^{2})^{0.5}

6^{x}

\frac{( ln ( x ) ) ^{3}}{x}

What is the integral of 2/((1+x^2)) ?
The integral of 2/((1+x^2)) is 2arctan(x)+C