What is the integral of cos((1/4)x) ?

The integral of cos((1/4)x) is 4sin(1/4 x)+C

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integral of cos((1/4)x)

integral

cos ((\frac{1}{4}) x)

4 sin (\frac{1}{4} x) + C

Solution steps

\int cos (\frac{1}{4} x) d x

Apply u-substitution

: \int cos (u) \cdot 4 d u

= \int cos (u) \cdot 4 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 4 sin (u)

Substitute back

u = \frac{1}{4} x

= 4 sin (\frac{1}{4} x)

Add a constant to the solution

= 4 sin (\frac{1}{4} x) + C

(t^{2} - 6 t + 13)^{- 1}

\frac{( 1 + x ) ^{3}}{x}

(ln (x))^{4}

(\frac{4 + x}{2})^{3}

\frac{u}{( 1 + u ^{2} )}

What is the integral of cos((1/4)x) ?
The integral of cos((1/4)x) is 4sin(1/4 x)+C