What is the integral of-5cos(x/2) ?

The integral of-5cos(x/2) is -10sin(x/2)+C

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integral of-5cos(x/2)

integral

- 5 cos (\frac{x}{2})

- 10 sin (\frac{x}{2}) + C

Solution steps

\int - 5 cos (\frac{x}{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5 \cdot \int cos (\frac{x}{2}) d x

Apply u-substitution

: \int cos (u) \cdot 2 d u

= - 5 \cdot \int cos (u) \cdot 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5 \cdot 2 \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - 5 \cdot 2 sin (u)

Substitute back

u = \frac{x}{2}

= - 5 \cdot 2 sin (\frac{x}{2})

Simplify

= - 10 sin (\frac{x}{2})

Add a constant to the solution

= - 10 sin (\frac{x}{2}) + C

e^{(x^{2}) - x}

\frac{1}{( x ^{2} + a ) ^{2}}

\frac{sin ^{2} ( 2 x )}{cos ^{2} ( x )}

e^{\frac{- x ^{2}}{3}}

\frac{( x + 2 )}{( x ^{2} + 1 )}