What is the integral of ((x-3))/((x^2-3x+2)) ?

The integral of ((x-3))/((x^2-3x+2)) is 2ln|x-1|-ln|x-2|+C

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integral of ((x-3))/((x^2-3x+2))

integral

\frac{( x - 3 )}{( x ^{2} - 3 x + 2 )}

2 ln ∣ x - 1 ∣ - ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{x - 3}{x ^{2} - 3 x + 2} d x

Take the partial fraction of

\frac{x - 3}{x ^{2} - 3 x + 2} : \frac{2}{x - 1} - \frac{1}{x - 2}

= \int \frac{2}{x - 1} - \frac{1}{x - 2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x - 1} d x - \int \frac{1}{x - 2} d x

\int \frac{2}{x - 1} d x = 2 ln ∣ x - 1 ∣

\int \frac{1}{x - 2} d x = ln ∣ x - 2 ∣

= 2 ln ∣ x - 1 ∣ - ln ∣ x - 2 ∣

Add a constant to the solution

= 2 ln ∣ x - 1 ∣ - ln ∣ x - 2 ∣ + C

\frac{x ^{3}}{x ^{4} + 1}

e^{3 x - 1}

e^{2}

e^{3 x - 2}

f (x) = (\frac{x}{x + 40})^{\frac{1}{2}}

What is the integral of ((x-3))/((x^2-3x+2)) ?
The integral of ((x-3))/((x^2-3x+2)) is 2ln|x-1|-ln|x-2|+C