What is the integral of 2x(x^2+3)^{3/2} ?

The integral of 2x(x^2+3)^{3/2} is 2/5 (x^2+3)^{5/2}+C

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integral of 2x(x^2+3)^{3/2}

integral

2 x (x^{2} + 3)^{\frac{3}{2}}

\frac{2}{5} (x^{2} + 3)^{\frac{5}{2}} + C

Solution steps

\int 2 x (x^{2} + 3)^{\frac{3}{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x (x^{2} + 3)^{\frac{3}{2}} d x

Apply u-substitution

: \int \frac{u ^{\frac{3}{2}}}{2} d u

= 2 \cdot \int \frac{u ^{\frac{3}{2}}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int u^{\frac{3}{2}} d u

Apply the Power Rule

: \frac{2}{5} u^{\frac{5}{2}}

= 2 \cdot \frac{1}{2} \cdot \frac{2}{5} u^{\frac{5}{2}}

Substitute back

u = x^{2} + 3

= 2 \cdot \frac{1}{2} \cdot \frac{2}{5} (x^{2} + 3)^{\frac{5}{2}}

Simplify

2 \cdot \frac{1}{2} \cdot \frac{2}{5} (x^{2} + 3)^{\frac{5}{2}} : \frac{2}{5} (x^{2} + 3)^{\frac{5}{2}}

= \frac{2}{5} (x^{2} + 3)^{\frac{5}{2}}

Add a constant to the solution

= \frac{2}{5} (x^{2} + 3)^{\frac{5}{2}} + C

y = sin^{2} (x)

\frac{1}{( x ^{4} )}

lo g_{10} (\frac{( 1 + x )}{( 1 - x )})

\frac{1}{y ^{3}}

x^{2} - a^{2}

What is the integral of 2x(x^2+3)^{3/2} ?
The integral of 2x(x^2+3)^{3/2} is 2/5 (x^2+3)^{5/2}+C