What is the integral of 2/(x^{1/3)} ?

The integral of 2/(x^{1/3)} is 3x^{2/3}+C

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integral of 2/(x^{1/3)}

integral

\frac{2}{x ^{\frac{1}{3}}}

3 x^{\frac{2}{3}} + C

Solution steps

\int \frac{2}{x ^{\frac{1}{3}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ^{\frac{1}{3}}} d x

Apply the Power Rule

: \frac{3}{2} x^{\frac{2}{3}}

= 2 \cdot \frac{3}{2} x^{\frac{2}{3}}

Simplify

2 \cdot \frac{3}{2} x^{\frac{2}{3}} : 3 x^{\frac{2}{3}}

= 3 x^{\frac{2}{3}}

Add a constant to the solution

= 3 x^{\frac{2}{3}} + C

\frac{1}{( t t ^{2} - 1 )}

(x + 1)^{- 3}

\frac{1}{a + x ^{2}}

((e)^{x})^{2}

cos^{2} (t) sin (t)