What is the integral of x^2sqrt(x*1) ?

The integral of x^2sqrt(x*1) is 2/7 x^{7/2}+C

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integral of x^2sqrt(x*1)

integral

x^{2} x \cdot 1

\frac{2}{7} x^{\frac{7}{2}} + C

Solution steps

\int x^{2} x \cdot 1 d x

Simplify

= \int x^{2} x d x

Simplify

x^{2} x : x^{\frac{5}{2}}

= \int x^{\frac{5}{2}} d x

Apply the Power Rule

: \frac{2}{7} x^{\frac{7}{2}}

= \frac{2}{7} x^{\frac{7}{2}}

Add a constant to the solution

= \frac{2}{7} x^{\frac{7}{2}} + C

\frac{x}{( x ^{2} + x + 1 )}

sin^{3} (x) cos^{2} (x)

\frac{x}{( x ^{2} + 4 ) ^{2}}

(lo g_{10} (x))^{2}

x^{2} e^{3 x + 1}

What is the integral of x^2sqrt(x*1) ?
The integral of x^2sqrt(x*1) is 2/7 x^{7/2}+C