What is the solution for y^{''}+y= 1/(sin(x)) ?

The solution for y^{''}+y= 1/(sin(x)) is y=c_{1}cos(x)+c_{2}sin(x)-xcos(x)+ln(sin(x))sin(x)

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y^{''}+y= 1/(sin(x))

y^{^{''}} + y = \frac{1}{sin ( x )}

y = c_{1} cos (x) + c_{2} sin (x) - x cos (x) + ln (sin (x)) sin (x)

Solution steps

y^{''} (x) + y = \frac{1}{sin ( x )}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - x cos (x) + ln (sin (x)) sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - x cos (x) + ln (sin (x)) sin (x)

y^{^{''}} - 4 y^{^{'}} - 5 y = 4 x^{2} e^{2 x}

(d^{2} - 6 d + 9) \cdot y = x^{2} \cdot e^{2 x}

0.2 y^{^{''}} + 1.2 y^{^{'}} + 2 y = 5 cos (x)

(d^{2} + 4 d) y = 2 sin (3 x)

y^{^{''}} + 9 y = 27 x^{2}

What is the solution for y^{''}+y= 1/(sin(x)) ?
The solution for y^{''}+y= 1/(sin(x)) is y=c_{1}cos(x)+c_{2}sin(x)-xcos(x)+ln(sin(x))sin(x)