What is the integral of 36t^8e^{-t^9} ?

The integral of 36t^8e^{-t^9} is -4e^{-t^9}+C

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integral of 36t^8e^{-t^9}

\int 36 t^{8} e^{- t^{9}} d t

- 4 e^{- t^{9}} + C

Solution steps

\int 36 t^{8} e^{- t^{9}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 36 \cdot \int t^{8} e^{- t^{9}} d t

Apply u-substitution

: \int - \frac{e ^{u}}{9} d u

= 36 \cdot \int - \frac{e ^{u}}{9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 36 (- \frac{1}{9} \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 36 (- \frac{1}{9} e^{u})

Substitute back

u = - t^{9}

= 36 (- \frac{1}{9} e^{- t^{9}})

Simplify

36 (- \frac{1}{9} e^{- t^{9}}) : - 4 e^{- t^{9}}

= - 4 e^{- t^{9}}

Add a constant to the solution

= - 4 e^{- t^{9}} + C

x \to - 1 lim (5 - 11 x)

\frac{\partial}{\partial x} (\frac{x}{y ^{2}} + x y + 2)

x^{2} + 5

\frac{d}{d x} (\frac{x ^{3}}{3} + 7 x^{2} + 50 x)

\frac{\partial}{\partial x} (5 arccot (x))

What is the integral of 36t^8e^{-t^9} ?
The integral of 36t^8e^{-t^9} is -4e^{-t^9}+C