What is the solution for (d^3-3d+2)*y=x+1 ?

The solution for (d^3-3d+2)*y=x+1 is y=c_{1}e^{-2x}+c_{2}e^x+c_{3}xe^x+x/2+5/4

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(d^3-3d+2)*y=x+1

(d^{3} - 3 d + 2) \cdot y = x + 1

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x} + \frac{x}{2} + \frac{5}{4}

Solution steps

(d^{3} - 3 d + 2) y = x + 1

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x} + \frac{x}{2} + \frac{5}{4}

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x} + \frac{x}{2} + \frac{5}{4}

(d^{2} + 4) \cdot y = 4 tan^{2} (x)

y^{^{''}} - 3 y^{^{'}} = x + 3

x^{^{''}} - x^{^{'}} - 2 = 5 cos (2 t)

(d^{2} - 8 d + 20) \cdot y = 100 x^{2} - 26 x \cdot e^{x}

(d^{2} + 4 d + 5) \cdot y = e^{- 2 x}

What is the solution for (d^3-3d+2)*y=x+1 ?
The solution for (d^3-3d+2)*y=x+1 is y=c_{1}e^{-2x}+c_{2}e^x+c_{3}xe^x+x/2+5/4