What is the derivative of (2x-8^4(x^2+x+1)^5) ?

The derivative of (2x-8^4(x^2+x+1)^5) is 8(2x-8)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-8)^4

What is the first derivative of (2x-8^4(x^2+x+1)^5) ?

The first derivative of (2x-8^4(x^2+x+1)^5) is 8(2x-8)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-8)^4

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\frac{d}{d x} ((2 x - 8)^{4} (x^{2} + x + 1)^{5})

8 (2 x - 8)^{3} (x^{2} + x + 1)^{5} + 5 (x^{2} + x + 1)^{4} (2 x + 1) (2 x - 8)^{4}

Solution steps

\frac{d}{d x} ((2 x - 8)^{4} (x^{2} + x + 1)^{5})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (2 x - 8)^{4}, g = (x^{2} + x + 1)^{5}

= \frac{d}{d x} ((2 x - 8)^{4}) (x^{2} + x + 1)^{5} + \frac{d}{d x} ((x^{2} + x + 1)^{5}) (2 x - 8)^{4}

\frac{d}{d x} ((2 x - 8)^{4}) = 8 (2 x - 8)^{3}

\frac{d}{d x} ((x^{2} + x + 1)^{5}) = 5 (x^{2} + x + 1)^{4} (2 x + 1)

= 8 (2 x - 8)^{3} (x^{2} + x + 1)^{5} + 5 (x^{2} + x + 1)^{4} (2 x + 1) (2 x - 8)^{4}

\int \frac{e ^{x - y}}{1 + e ^{x}}

\frac{d}{d x} (lo g_{3} (3 x - 7))

\int 8 x e^{15 x} d x

\frac{d}{d x} (\frac{- x ^{2} + y ^{2}}{( x ^{2} + y ^{2} ) ^{2}})

\frac{d y}{d t} = - \frac{y}{t} + 2

What is the derivative of (2x-8^4(x^2+x+1)^5) ?
The derivative of (2x-8^4(x^2+x+1)^5) is 8(2x-8)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-8)^4
What is the first derivative of (2x-8^4(x^2+x+1)^5) ?
The first derivative of (2x-8^4(x^2+x+1)^5) is 8(2x-8)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-8)^4