What is the solution for (d^2-2d)y=x^3 ?

The solution for (d^2-2d)y=x^3 is y=c_{1}e^{2x}+c_{2}-(x^4)/8-(x^3)/4-(3x^2)/8-(3x)/8

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(d^2-2d)y=x^3

(d^{2} - 2 d) y = x^{3}

y = c_{1} e^{2 x} + c_{2} - \frac{x ^{4}}{8} - \frac{x ^{3}}{4} - \frac{3 x ^{2}}{8} - \frac{3 x}{8}

Solution steps

(d^{2} - 2 d) y = x^{3}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} - \frac{x ^{4}}{8} - \frac{x ^{3}}{4} - \frac{3 x ^{2}}{8} - \frac{3 x}{8}

y = c_{1} e^{2 x} + c_{2} - \frac{x ^{4}}{8} - \frac{x ^{3}}{4} - \frac{3 x ^{2}}{8} - \frac{3 x}{8}

y^{^{''}} + 2 y^{^{'}} + 5 y = e^{- t} sin (t)

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2} x

(d^{3} - 7 d - 6) y = e^{2} x (1 + x)

(d^{4} - 1) y = 7 x^{2}

(d^{3} - 5 d^{2} + 8 d - 4) y = e^{2} x

What is the solution for (d^2-2d)y=x^3 ?
The solution for (d^2-2d)y=x^3 is y=c_{1}e^{2x}+c_{2}-(x^4)/8-(x^3)/4-(3x^2)/8-(3x)/8