What is the answer to solvefor d,d(q)=-0.4q+23 ?

The answer to solvefor d,d(q)=-0.4q+23 is d=(-2q+115)/(5q);\quad q\ne 0

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solvefor d,d(q)=-0.4q+23

solve for

d, d (q) = - 0.4 q + 23

d = \frac{- 2 q + 115}{5 q}; q \neq = 0

Solution steps

d (q) = - 0.4 q + 23

Multiply both sides by

10

d q \cdot 10 = - 4 q + 230

Divide both sides by

q \cdot 10; q \neq = 0

d = \frac{- 2 q + 115}{5 q}; q \neq = 0

(d^{2} + 4) y = 4 sin^{2} (x)

(d^{4} + 2 d^{3} - 3 d^{2}) y = 3 e^{2} x + 4 sin (x)

(d^{2} - 4) y = 3 e^{2} x - 4 e^{- 2} x

y^{^{''}} + 4 y = e^{2} t

(d^{2} + 10 d + 25) y = e^{- 5 x}

What is the answer to solvefor d,d(q)=-0.4q+23 ?
The answer to solvefor d,d(q)=-0.4q+23 is d=(-2q+115)/(5q);\quad q\ne 0