What is implicit (dy)/(dx),xy+x=2 ?

The answer to implicit (dy)/(dx),xy+x=2 is (dy}{dx}=\frac{-y-1)/x

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implicit (dy)/(dx),xy+x=2

implicit derivative

\frac{d y}{d x}, x y + x = 2

\frac{d y}{d x} = \frac{- y - 1}{x}

Solution steps

x y + x = 2

Treat

y

y (x)

Differentiate both sides:

y + x \frac{d y}{d x} + 1 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- y - 1}{x}

\frac{d y}{d x} = \frac{- y - 1}{x}

\int \frac{a ^{2} + x ^{2}}{x ^{2}} d x

y = 6 x - x^{2}, y = x

\int_{5}^{8} \frac{5}{x - 5} d x

\frac{\partial}{\partial x} \frac{u}{1 + 2.4 ( \frac{x}{y} )}

\frac{\partial}{\partial x} (6 x^{5} y^{6} + 5 x^{4} y^{7})

What is implicit (dy)/(dx),xy+x=2 ?
The answer to implicit (dy)/(dx),xy+x=2 is (dy}{dx}=\frac{-y-1)/x