What is the solution for (d^3-d)*y=x ?

The solution for (d^3-d)*y=x is y=c_{1}+c_{2}e^{-x}+c_{3}e^x-(x^2)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^3-d)*y=x

(d^{3} - d) \cdot y = x

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{x ^{2}}{2}

Solution steps

(d^{3} - d) y = x

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{x ^{2}}{2}

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{x ^{2}}{2}

(d^{2} + 2 d + 3) y = sin (x)

y^{^{'''}} - 3 y^{^{''}} + 4 y^{^{'}} - 2 y = e^{x}

y^{^{''}} - 6 y^{^{'}} + 9 y = 2, y^{^{'}} (0) = 17

(d^{2} - 1) y = x sin^{3} (x) + cos (x)

(d^{4} + 8 d^{2} + 16) \cdot y = - 2

What is the solution for (d^3-d)*y=x ?
The solution for (d^3-d)*y=x is y=c_{1}+c_{2}e^{-x}+c_{3}e^x-(x^2)/2