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Popular >

(d^2-1)y=x

Solution

(d^{2} - 1) y = x

Solution

y = c_{1} e^{x} + c_{2} e^{- x} - x

Solution steps

(d^{2} - 1) y = x

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - x

y = c_{1} e^{x} + c_{2} e^{- x} - x

Popular Examples

(d^2+2)y=x^2e^3x

(d^{2} + 2) y = x^{2} e^{3} x

y^{''}-4y^'+4y=(x+1)e^2x

y^{^{''}} - 4 y^{^{'}} + 4 y = (x + 1) e^{2} x

(d^2-4d-12)*y=(x-1)*e^{-2x}

(d^{2} - 4 d - 12) \cdot y = (x - 1) \cdot e^{- 2 x}

(d^2+4d+4)y=x^2+e^x+cos(x)

(d^{2} + 4 d + 4) y = x^{2} + e^{x} + cos (x)

(d^2-3d+2)y=5e^3x

(d^{2} - 3 d + 2) y = 5 e^{3} x

Frequently Asked Questions (FAQ)

What is the solution for (d^2-1)y=x ?
The solution for (d^2-1)y=x is y=c_{1}e^x+c_{2}e^{-x}-x