What is the solution for y^{''}-3y^'+2y=6x-11 ?

The solution for y^{''}-3y^'+2y=6x-11 is y=c_{1}e^{2x}+c_{2}e^x+3x-1

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y^{''}-3y^'+2y=6x-11

y^{^{''}} - 3 y^{^{'}} + 2 y = 6 x - 11

y = c_{1} e^{2 x} + c_{2} e^{x} + 3 x - 1

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = 6 x - 11

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + 3 x - 1

y = c_{1} e^{2 x} + c_{2} e^{x} + 3 x - 1

y^{^{''}} + y = sec (x^{3})

(d^{2} - d - 12) \cdot y = e^{3 x}

y^{^{''}} - y^{^{'}} = \frac{e ^{2} x}{( 2 + e ^{x} )}

2 y^{^{'''}} - y^{^{''}} - 2 y^{^{'}} + y = sin (x)

d, d (t) = 4000 - 3000 e^{- 0.06 t}

What is the solution for y^{''}-3y^'+2y=6x-11 ?
The solution for y^{''}-3y^'+2y=6x-11 is y=c_{1}e^{2x}+c_{2}e^x+3x-1