What is the solution for y^{''}-y^'-6y=11 ?

The solution for y^{''}-y^'-6y=11 is y=c_{1}e^{3t}+c_{2}e^{-2t}-11/6

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y^{''}-y^'-6y=11

y^{^{''}} - y^{^{'}} - 6 y = 11

y = c_{1} e^{3 t} + c_{2} e^{- 2 t} - \frac{11}{6}

Solution steps

y^{''} (t) - y^{'} (t) - 6 y = 11

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 2 t} - \frac{11}{6}

y = c_{1} e^{3 t} + c_{2} e^{- 2 t} - \frac{11}{6}

(d + 2) (d - 1)^{3} y = e^{x}

(d^{4} - 1) y = e^{x} cos (x) cos^{3} (x)

(d^{2} - 4 d + 4) \cdot y = 8 e^{2 x} \cdot x^{2} \cdot sin^{2} (x)

y^{^{''}} - 3 y^{^{'}} + 2 y = 4 t - 8

(d^{3} - 2 d + 4) y = 3 x^{2} - 5 x + 2

What is the solution for y^{''}-y^'-6y=11 ?
The solution for y^{''}-y^'-6y=11 is y=c_{1}e^{3t}+c_{2}e^{-2t}-11/6