What is the solution for (d^2+3d+2)y=e^{e^x} ?

The solution for (d^2+3d+2)y=e^{e^x} is y=c_{1}e^{-x}+c_{2}e^{-2x}+e^{e^x-2x}

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(d^2+3d+2)y=e^{e^x}

(d^{2} + 3 d + 2) y = e^{e^{x}}

y = c_{1} e^{- x} + c_{2} e^{- 2 x} + e^{e^{x} - 2 x}

Solution steps

(d^{2} + 3 d + 2) y = e^{e^{x}}

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} e^{- 2 x} + e^{e^{x} - 2 x}

y = c_{1} e^{- x} + c_{2} e^{- 2 x} + e^{e^{x} - 2 x}

(d^{2} - 6 d + 9) y = 2 e^{3} x

y^{^{''}} + 3 y^{^{'}} + 2 y = (e^{e})^{x}

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 e^{x}

(d^{2} - 1) \cdot y = x \cdot sin (x) + x^{2} \cdot e^{x}

d, d (x) = \frac{1}{36 ( x - 60 ) ^{2} - 100}

What is the solution for (d^2+3d+2)y=e^{e^x} ?
The solution for (d^2+3d+2)y=e^{e^x} is y=c_{1}e^{-x}+c_{2}e^{-2x}+e^{e^x-2x}