What is the solution for (d^2-4d+4)*y=x^3 ?

The solution for (d^2-4d+4)*y=x^3 is y=c_{1}e^{2x}+c_{2}xe^{2x}+(x^3)/4+(3x^2)/4+(9x)/8+3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2-4d+4)*y=x^3

(d^{2} - 4 d + 4) \cdot y = x^{3}

y = c_{1} e^{2 x} + c_{2} x e^{2 x} + \frac{x ^{3}}{4} + \frac{3 x ^{2}}{4} + \frac{9 x}{8} + \frac{3}{4}

Solution steps

(d^{2} - 4 d + 4) y = x^{3}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} x e^{2 x} + \frac{x ^{3}}{4} + \frac{3 x ^{2}}{4} + \frac{9 x}{8} + \frac{3}{4}

y = c_{1} e^{2 x} + c_{2} x e^{2 x} + \frac{x ^{3}}{4} + \frac{3 x ^{2}}{4} + \frac{9 x}{8} + \frac{3}{4}

(d^{3} - 25 d) y = sin^{2} (x) cos^{2} (x)

(d^{3} - 3 d - 2) y = x^{3}

y^{^{''}} + y^{^{'}} - 2 y = 14 + 2 x - 2 x^{2}

y^{^{''}} - 5 y^{^{'}} + 6 y = x^{2} + x

(d^{2} - 4 d + 4) \cdot y = 12 \cdot (1 + x)^{2} \cdot e^{2 x}

What is the solution for (d^2-4d+4)*y=x^3 ?
The solution for (d^2-4d+4)*y=x^3 is y=c_{1}e^{2x}+c_{2}xe^{2x}+(x^3)/4+(3x^2)/4+(9x)/8+3/4