What is the derivative of 6x^{1/4} ?

The derivative of 6x^{1/4} is 3/(2x^{3/4)}

What is the first derivative of 6x^{1/4} ?

The first derivative of 6x^{1/4} is 3/(2x^{3/4)}

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derivative of

6 x^{\frac{1}{4}}

\frac{3}{2 x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (6 x^{\frac{1}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

6 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : \frac{3}{2 x ^{\frac{3}{4}}}

= \frac{3}{2 x ^{\frac{3}{4}}}

\int \frac{3 x}{( 1 - x ^{2} ) ^{3}} d x

e^{y} d x + x e^{y} d y = 0

\frac{\partial}{\partial x} (cos^{2} (x))

(x^{2} (x^{2} + 9 x))^{6}

\frac{\partial}{\partial x} (ln (x + y^{2}))

What is the derivative of 6x^{1/4} ?
The derivative of 6x^{1/4} is 3/(2x^{3/4)}
What is the first derivative of 6x^{1/4} ?
The first derivative of 6x^{1/4} is 3/(2x^{3/4)}