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Popular >

y^'-2x^2=0

Solution

y^{^{'}} - 2 x^{2} = 0

Solution

y = \frac{2 x ^{3}}{3} + c_{1}

Solution steps

y^{'} (x) - 2 x^{2} = 0

Isolate

y^{'} (x) : y^{'} (x) = 2 x^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 x^{2} d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3} + c_{1}

y = \frac{2 x ^{3}}{3} + c_{1}

Popular Examples

y^'=3,0.4-0.24y^2y(0)=0

y^{^{'}} = 3, 0.4 - 0.24 y^{2} y (0) = 0

f^'(x)=-sin(x^5)-78x

f^{^{'}} (x) = - sin (x^{5}) - 78 x

y^'=2,xy^2y= 1/((4-x^2))

y^{^{'}} = 2, x y^{2} y = \frac{1}{( 4 - x ^{2} )}

f^'(x)=x^3+8x-5x+6

f^{^{'}} (x) = x^{3} + 8 x - 5 x + 6

y^'=((2))/((x^3)+5x^{\frac{(2)){(3)}}}

y^{^{'}} = \frac{( 2 )}{( x ^{3} ) + 5 x ^{\frac{( 2 )}{( 3 )}}}

Frequently Asked Questions (FAQ)

What is the solution for y^'-2x^2=0 ?
The solution for y^'-2x^2=0 is y=(2x^3)/3+c_{1}