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Popular >

18x+y^'=20,-3xy(1)=2

Solution

18 x + y^{^{'}} = 20, - 3 x y (1) = 2

Solution

y = 20 x - 9 x^{2} + c_{1}

Solution steps

18 x + y^{'} (x) = 20

Isolate

y^{'} (x) : y^{'} (x) = 20 - 18 x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 20 - 18 x d x

\int 20 - 18 x d x = 20 x - 9 x^{2} + c_{1}

y = 20 x - 9 x^{2} + c_{1}

Popular Examples

2y^'=((1-sin(x))^{-1})/2

2 y^{^{'}} = \frac{( 1 - sin ( x ) ) ^{- 1}}{2}

f^'(x)=2(x^2+x)^5

f^{^{'}} (x) = 2 (x^{2} + x)^{5}

(x^2y^{''}+1)/(4(x+3/4)y)=0

\frac{x ^{2} y ^{^{''}} + 1}{4 ( x + \frac{3}{4} ) y} = 0

f^'(x)=(x^2+x-1)/(x+1)

f^{^{'}} (x) = \frac{x ^{2} + x - 1}{x + 1}

f^'(t)=e^{-t}*(8-8t)

f^{^{'}} (t) = e^{- t} \cdot (8 - 8 t)

Frequently Asked Questions (FAQ)

What is the solution for 18x+y^'=20,-3xy(1)=2 ?
The solution for 18x+y^'=20,-3xy(1)=2 is y=20x-9x^2+c_{1}