What is the solution for (y^{''}+1)/(y^2)=0 ?

The solution for (y^{''}+1)/(y^2)=0 is y=-(t^2)/2+c_{1}t+c_{2}

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(y^{''}+1)/(y^2)=0

\frac{y ^{^{''}} + 1}{y ^{2}} = 0

y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

Solution steps

\frac{y ^{''} ( t ) + 1}{y ^{2}} = 0

Isolate

y^{''} (t) : y^{''} (t) = - 1

Solve

y^{''} (t) = - 1 : y^{'} (t) = - t + c_{1}

Solve

y^{'} (t) = - t + c_{1} : y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

y^{^{'}} - e^{4} x = 0

x \to 3 lim ((\frac{1 + 1}{x})^{x})

x \to 3 lim ((\frac{1 - 1}{x})^{x})

x \to 3 lim (\frac{1}{cot ^{3} ( x )})

x \to 3 lim (ln (\frac{1}{x}))

What is the solution for (y^{''}+1)/(y^2)=0 ?
The solution for (y^{''}+1)/(y^2)=0 is y=-(t^2)/2+c_{1}t+c_{2}